Square root of 2340

The square root of 2340 is 48.373546 (rounded to 6 decimal places). In simplest radical form it is 6√65.

Square root of 2340

Pick any whole number from 1 to 10,000.

\sqrt{2340} = 6\sqrt{65} \approx 48.373546

How to work it out

1
The square root of 2340 is the number that multiplied by itself gives 2340.
2
2340 is between the perfect squares 48² = 2304 and 49² = 2401, so its square root is between 48 and 49.
3
Pull out the biggest square factor: 2340 = 36 × 65, so
$\sqrt{2340} = \sqrt{36 \times 65} = 6\sqrt{65}$
4
A calculator, or long division of digits, gives
$\sqrt{2340} \approx 48.373546$

LaTeX source of the formulas on this page

\[ \sqrt{2340} = 6\sqrt{65} \approx 48.373546 \]
\[ \sqrt{2340} = \sqrt{36 \times 65} = 6\sqrt{65} \]
\[ \sqrt{2340} \approx 48.373546 \]

What is the square root of 2340?

The square root of 2340 is 48.373546 (rounded to 6 decimal places). In simplest radical form it is 6√65.

Is 2340 a perfect square?

No. It lies between 48² = 2304 and 49² = 2401.

What is 2340 squared?

2340 × 2340 = 5475600.

What is the square root of 2340 rounded to 2 decimals?

48.37.