Square root of 1998

The square root of 1998 is 44.698993 (rounded to 6 decimal places). In simplest radical form it is 3√222.

Square root of 1998

Pick any whole number from 1 to 10,000.

\sqrt{1998} = 3\sqrt{222} \approx 44.698993

How to work it out

1
The square root of 1998 is the number that multiplied by itself gives 1998.
2
1998 is between the perfect squares 44² = 1936 and 45² = 2025, so its square root is between 44 and 45.
3
Pull out the biggest square factor: 1998 = 9 × 222, so
$\sqrt{1998} = \sqrt{9 \times 222} = 3\sqrt{222}$
4
A calculator, or long division of digits, gives
$\sqrt{1998} \approx 44.698993$

LaTeX source of the formulas on this page

\[ \sqrt{1998} = 3\sqrt{222} \approx 44.698993 \]
\[ \sqrt{1998} = \sqrt{9 \times 222} = 3\sqrt{222} \]
\[ \sqrt{1998} \approx 44.698993 \]

What is the square root of 1998?

The square root of 1998 is 44.698993 (rounded to 6 decimal places). In simplest radical form it is 3√222.

Is 1998 a perfect square?

No. It lies between 44² = 1936 and 45² = 2025.

What is 1998 squared?

1998 × 1998 = 3992004.

What is the square root of 1998 rounded to 2 decimals?

44.70.