Square root of 1968

The square root of 1968 is 44.362146 (rounded to 6 decimal places). In simplest radical form it is 4√123.

Square root of 1968

Pick any whole number from 1 to 10,000.

\sqrt{1968} = 4\sqrt{123} \approx 44.362146

How to work it out

1
The square root of 1968 is the number that multiplied by itself gives 1968.
2
1968 is between the perfect squares 44² = 1936 and 45² = 2025, so its square root is between 44 and 45.
3
Pull out the biggest square factor: 1968 = 16 × 123, so
$\sqrt{1968} = \sqrt{16 \times 123} = 4\sqrt{123}$
4
A calculator, or long division of digits, gives
$\sqrt{1968} \approx 44.362146$

LaTeX source of the formulas on this page

\[ \sqrt{1968} = 4\sqrt{123} \approx 44.362146 \]
\[ \sqrt{1968} = \sqrt{16 \times 123} = 4\sqrt{123} \]
\[ \sqrt{1968} \approx 44.362146 \]

What is the square root of 1968?

The square root of 1968 is 44.362146 (rounded to 6 decimal places). In simplest radical form it is 4√123.

Is 1968 a perfect square?

No. It lies between 44² = 1936 and 45² = 2025.

What is 1968 squared?

1968 × 1968 = 3873024.

What is the square root of 1968 rounded to 2 decimals?

44.36.