The number 9953
9953 is a composite number with 4 divisors. Its prime factorisation is 37 × 269. Divisors (4): 1, 37, 269, 9953.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 9953: a semiprime: 37 × 269, the product of two primes.
- 2
9953 is composite. Its prime factorisation is
- 3
The divisors add up to 10260; without 9953 itself that is 307, so 9953 is deficient (307 is less than 9953). Euler's totient φ(9953) = 9648 numbers up to 9953 share no factor with it.
- 4
The digits of 9953 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 73 steps to reach 1.
LaTeX source of the formulas on this page
\[ 9953 = 37 \times 269 \]
9953 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 10260 |
| Euler totient φ(n) | 9648 |
| Square | 99062209 |
| Cube | 985966166177 |
| Square root | 99.764723 |
| Digit sum / digital root | 26 / 8 |
| Collatz steps to 1 | 73 |
| Scientific notation | 9.953 × |
9953 in other forms
| Form | Value |
|---|---|
| In words | nine thousand nine hundred and fifty-three |
| Binary (base 2) | 10011011100001 |
| Octal (base 8) | 23341 |
| Hexadecimal (base 16) | 26E1 |
| Base 3 | 111122122 |
| As time | 9953 seconds = 2 h 45 min 53 s |
Is 9953 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 9953 a prime number?
No. 9953 = 37 × 269, so it is divisible by 37.
What are the factors of 9953?
1, 37, 269, 9953.
What is 9953 in binary?
10011011100001 (hexadecimal 26E1, octal 23341).
What is the square root of 9953?
About 99.7647.
Is 9953 divisible by 3?
No. Its digits add up to 26, which is not a multiple of 3.
What is special about the number 9953?
9953 is a semiprime: 37 × 269, the product of two primes.