The number 9939
9939 is a composite number with 4 divisors. Its prime factorisation is 3 × 3313. Divisors (4): 1, 3, 3313, 9939.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 9939: a semiprime: 3 × 3313, the product of two primes.
- 2
9939 is composite. Its prime factorisation is
- 3
The divisors add up to 13256; without 9939 itself that is 3317, so 9939 is deficient (3317 is less than 9939). Euler's totient φ(9939) = 6624 numbers up to 9939 share no factor with it.
- 4
The digits of 9939 add up to 30, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 73 steps to reach 1.
LaTeX source of the formulas on this page
\[ 9939 = 3 \times 3313 \]
9939 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 13256 |
| Euler totient φ(n) | 6624 |
| Square | 98783721 |
| Cube | 981811403019 |
| Square root | 99.694533 |
| Digit sum / digital root | 30 / 3 |
| Collatz steps to 1 | 73 |
| Scientific notation | 9.939 × |
9939 in other forms
| Form | Value |
|---|---|
| In words | nine thousand nine hundred and thirty-nine |
| Binary (base 2) | 10011011010011 |
| Octal (base 8) | 23323 |
| Hexadecimal (base 16) | 26D3 |
| Base 3 | 111122010 |
| As time | 9939 seconds = 2 h 45 min 39 s |
Is 9939 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (9939 ÷ 3 = 3313) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 9939 a prime number?
No. 9939 = 3 × 3313, so it is divisible by 3.
What are the factors of 9939?
1, 3, 3313, 9939.
What is 9939 in binary?
10011011010011 (hexadecimal 26D3, octal 23323).
What is the square root of 9939?
About 99.6945.
Is 9939 divisible by 3?
Yes. Its digits add up to 30, a multiple of 3.
What is special about the number 9939?
9939 is a semiprime: 3 × 3313, the product of two primes.