The number 97643
97643 is a composite number with 16 divisors. Its prime factorisation is 7 × 13 × 29 × 37. Divisors (16): 1, 7, 13, 29, 37, 91, 203, 259, 377, 481, 1073, 2639, 3367, 7511, 13949, 97643.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 97643: a Harshad number: divisible by its digit sum 29.
- 2
97643 is composite. Its prime factorisation is
- 3
The divisors add up to 127680; without 97643 itself that is 30037, so 97643 is deficient (30037 is less than 97643). Euler's totient φ(97643) = 72576 numbers up to 97643 share no factor with it.
- 4
The digits of 97643 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 177 steps to reach 1.
LaTeX source of the formulas on this page
\[ 97643 = 7 \times 13 \times 29 \times 37 \]
97643 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 127680 |
| Euler totient φ(n) | 72576 |
| Square | 9534155449 |
| Cube | 930943540506707 |
| Square root | 312.478799 |
| Digit sum / digital root | 29 / 2 |
| Collatz steps to 1 | 177 |
| Scientific notation | 9.7643 × |
97643 in other forms
| Form | Value |
|---|---|
| In words | ninety-seven thousand six hundred and forty-three |
| Binary (base 2) | 10111110101101011 |
| Octal (base 8) | 276553 |
| Hexadecimal (base 16) | 17D6B |
| Base 3 | 11221221102 |
| As time | 97643 seconds = 27 h 7 min 23 s |
Is 97643 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (97643 ÷ 7 = 13949) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 97643 a prime number?
No. 97643 = 7 × 13 × 29 × 37, so it is divisible by 7.
What are the factors of 97643?
1, 7, 13, 29, 37, 91, 203, 259, 377, 481, 1073, 2639, 3367, 7511, 13949, 97643.
What is 97643 in binary?
10111110101101011 (hexadecimal 17D6B, octal 276553).
What is the square root of 97643?
About 312.4788.
Is 97643 divisible by 3?
No. Its digits add up to 29, which is not a multiple of 3.
What is special about the number 97643?
97643 is a Harshad number: divisible by its digit sum 29.