The number 97104

Q: Is 97104 a prime number?

No. 97104 = 2^4 × 3 × 7 × 17^2, so it is divisible by 2.

97104 is a composite number with 60 divisors. Its prime factorisation is $2^{4}$ × 3 × 7 × $17^{2}$ . Divisors (60): 1, 2, 3, 4, 6, 7, 8, 12, 14, 16, 17, 21, 24, 28, 34, 42 … 97104.

Number

Pick any whole number from 1 to 100,000.

97104 = 2^{4} \times 3 \times 7 \times 17^{2}

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How to work it out

1
What is special about 97104: a Harshad number: divisible by its digit sum 21.
2
97104 is composite. Its prime factorisation is
$97104 = 2^{4} \times 3 \times 7 \times 17^{2}$
3
The divisors add up to 304544; without 97104 itself that is 207440, so 97104 is abundant (207440 is more than 97104). Euler's totient φ(97104) = 26112 numbers up to 97104 share no factor with it.
4
The digits of 97104 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 66 steps to reach 1.

LaTeX source of the formulas on this page

\[ 97104 = 2^{4} \times 3 \times 7 \times 17^{2} \]

97104 at a glance

Property	Value
Type	composite
Number of divisors	60
Sum of divisors	304544
Euler totient φ(n)	26112
Square	9429186816
Cube	915611756580864
Square root	311.615147 (= 68√21)
Digit sum / digital root	21 / 3
Collatz steps to 1	66
Scientific notation	9.7104 × $10^{4}$

97104 in other forms

Form	Value
In words	ninety-seven thousand one hundred and four
Binary (base 2)	10111101101010000
Octal (base 8)	275520
Hexadecimal (base 16)	17B50
Base 3	11221012110
As time	97104 seconds = 26 h 58 min 24 s

Is 97104 divisible by 2 to 12?

Divisor	Answer	Rule
2	Yes (97104 ÷ 2 = 48552)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	Yes (97104 ÷ 3 = 32368)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	Yes (97104 ÷ 4 = 24276)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 4)	A number is divisible by 5 if the last digit is 0 or 5.
6	Yes (97104 ÷ 6 = 16184)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	Yes (97104 ÷ 7 = 13872)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	Yes (97104 ÷ 8 = 12138)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 3)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 4)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 7)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	Yes (97104 ÷ 12 = 8092)	A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 97104 a prime number?

No. 97104 = $2^{4}$ × 3 × 7 × $17^{2}$ , so it is divisible by 2.

What are the factors of 97104?

1, 2, 3, 4, 6, 7, 8, 12, 14, 16, 17, 21, 24, 28, 34, 42, 48, 51, 56, 68, 84, 102, 112, 119, 136, 168, 204, 238, 272, 289, 336, 357, 408, 476, 578, 714, 816, 867, 952, 1156, 1428, 1734, 1904, 2023, 2312, 2856, 3468, 4046, 4624, 5712, 6069, 6936, 8092, 12138, 13872, 16184, 24276, 32368, 48552, 97104.

What is 97104 in binary?

10111101101010000 (hexadecimal 17B50, octal 275520).

What is the square root of 97104?

About 311.6151, exactly 68√21.

Is 97104 divisible by 3?

Yes. Its digits add up to 21, a multiple of 3.

What is special about the number 97104?

97104 is a Harshad number: divisible by its digit sum 21.