The number 9555
9555 is a composite number with 24 divisors. Its prime factorisation is 3 × 5 × × 13. Divisors (24): 1, 3, 5, 7, 13, 15, 21, 35, 39, 49, 65, 91, 105, 147, 195, 245 … 9555.
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How to work it out
- 1
9555 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
9555 is composite. Its prime factorisation is
- 3
The divisors add up to 19152; without 9555 itself that is 9597, so 9555 is abundant (9597 is more than 9555). Euler's totient φ(9555) = 4032 numbers up to 9555 share no factor with it.
- 4
The digits of 9555 add up to 24, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 104 steps to reach 1.
LaTeX source of the formulas on this page
\[ 9555 = 3 \times 5 \times 7^{2} \times 13 \]9555 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 24 |
| Sum of divisors | 19152 |
| Euler totient φ(n) | 4032 |
| Square | 91298025 |
| Cube | 872352628875 |
| Square root | 97.749680 (= 7√195) |
| Digit sum / digital root | 24 / 6 |
| Collatz steps to 1 | 104 |
| Scientific notation | 9.555 × |
9555 in other forms
| Form | Value |
|---|---|
| In words | nine thousand five hundred and fifty-five |
| Binary (base 2) | 10010101010011 |
| Octal (base 8) | 22523 |
| Hexadecimal (base 16) | 2553 |
| Base 3 | 111002220 |
| As time | 9555 seconds = 2 h 39 min 15 s |
Is 9555 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (9555 ÷ 3 = 3185) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (9555 ÷ 5 = 1911) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (9555 ÷ 7 = 1365) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 9555 a prime number?
No. 9555 = 3 × 5 × × 13, so it is divisible by 3.
What are the factors of 9555?
1, 3, 5, 7, 13, 15, 21, 35, 39, 49, 65, 91, 105, 147, 195, 245, 273, 455, 637, 735, 1365, 1911, 3185, 9555.
What is 9555 in binary?
10010101010011 (hexadecimal 2553, octal 22523).
What is the square root of 9555?
About 97.7497, exactly 7√195.
Is 9555 divisible by 3?
Yes. Its digits add up to 24, a multiple of 3.
What is special about the number 9555?
It is a composite number with 24 divisors.