The number 925
925 is a composite number with 6 divisors. Its prime factorisation is Ć 37. Divisors (6): 1, 5, 25, 37, 185, 925.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
925 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
925 is composite. Its prime factorisation is
- 3
The divisors add up to 1178; without 925 itself that is 253, so 925 is deficient (253 is less than 925). Euler's totient Ļ(925) = 720 numbers up to 925 share no factor with it.
- 4
The digits of 925 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 129 steps to reach 1.
LaTeX source of the formulas on this page
\[ 925 = 5^{2} \times 37 \]925 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 1178 |
| Euler totient Ļ(n) | 720 |
| Square | 855625 |
| Cube | 791453125 |
| Square root | 30.413813 (= 5ā37) |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 129 |
| Scientific notation | 9.25 Ć |
925 in other forms
| Form | Value |
|---|---|
| In words | nine hundred and twenty-five |
| Roman numerals | CMXXV |
| Binary (base 2) | 1110011101 |
| Octal (base 8) | 1635 |
| Hexadecimal (base 16) | 39D |
| Base 3 | 1021021 |
| As time | 925 seconds = 15 min 25 s |
Is 925 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (925 Ć· 5 = 185) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 925 a prime number?
No. 925 = Ć 37, so it is divisible by 5.
What are the factors of 925?
1, 5, 25, 37, 185, 925.
What is 925 in binary?
1110011101 (hexadecimal 39D, octal 1635).
What is the square root of 925?
About 30.4138, exactly 5ā37.
What is 925 in Roman numerals?
CMXXV.
Is 925 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 925?
It is a composite number with 6 divisors.