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The number 91242

91242 is a composite number with 24 divisors. Its prime factorisation is 2 × 323^{2} × 37 × 137. Divisors (24): 1, 2, 3, 6, 9, 18, 37, 74, 111, 137, 222, 274, 333, 411, 666, 822 … 91242.

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How to work it out

  1. 1

    What is special about 91242: a Harshad number: divisible by its digit sum 18.

  2. 2

    91242 is composite. Its prime factorisation is

    91242=2×32×37×13791242 = 2 \times 3^{2} \times 37 \times 137
  3. 3

    The divisors add up to 204516; without 91242 itself that is 113274, so 91242 is abundant (113274 is more than 91242). Euler's totient φ(91242) = 29376 numbers up to 91242 share no factor with it.

  4. 4

    The digits of 91242 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 32 steps to reach 1.

LaTeX source of the formulas on this page
\[ 91242 = 2 \times 3^{2} \times 37 \times 137 \]

91242 at a glance

PropertyValue
Typecomposite
Number of divisors24
Sum of divisors204516
Euler totient φ(n)29376
Square8325102564
Cube759599008144488
Square root302.062907 (= 3√10138)
Digit sum / digital root18 / 9
Collatz steps to 132
Scientific notation9.1242 × 10410^{4}

91242 in other forms

FormValue
In wordsninety-one thousand two hundred and forty-two
Binary (base 2)10110010001101010
Octal (base 8)262152
Hexadecimal (base 16)1646A
Base 311122011100
As time91242 seconds = 25 h 20 min 42 s

Is 91242 divisible by 2 to 12?

DivisorAnswerRule
2Yes (91242 ÷ 2 = 45621)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (91242 ÷ 3 = 30414)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 2)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6Yes (91242 ÷ 6 = 15207)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 2)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (91242 ÷ 9 = 10138)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 2)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 6)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 91242 a prime number?

No. 91242 = 2 × 323^{2} × 37 × 137, so it is divisible by 2.

What are the factors of 91242?

1, 2, 3, 6, 9, 18, 37, 74, 111, 137, 222, 274, 333, 411, 666, 822, 1233, 2466, 5069, 10138, 15207, 30414, 45621, 91242.

What is 91242 in binary?

10110010001101010 (hexadecimal 1646A, octal 262152).

What is the square root of 91242?

About 302.0629, exactly 3√10138.

Is 91242 divisible by 3?

Yes. Its digits add up to 18, a multiple of 3.

What is special about the number 91242?

91242 is a Harshad number: divisible by its digit sum 18.

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