The number 9053
9053 is a composite number with 4 divisors. Its prime factorisation is 11 × 823. Divisors (4): 1, 11, 823, 9053.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 9053: a semiprime: 11 × 823, the product of two primes.
- 2
9053 is composite. Its prime factorisation is
- 3
The divisors add up to 9888; without 9053 itself that is 835, so 9053 is deficient (835 is less than 9053). Euler's totient φ(9053) = 8220 numbers up to 9053 share no factor with it.
- 4
The digits of 9053 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 39 steps to reach 1.
LaTeX source of the formulas on this page
\[ 9053 = 11 \times 823 \]
9053 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 9888 |
| Euler totient φ(n) | 8220 |
| Square | 81956809 |
| Cube | 741954991877 |
| Square root | 95.147254 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 39 |
| Scientific notation | 9.053 × |
9053 in other forms
| Form | Value |
|---|---|
| In words | nine thousand and fifty-three |
| Binary (base 2) | 10001101011101 |
| Octal (base 8) | 21535 |
| Hexadecimal (base 16) | 235D |
| Base 3 | 110102022 |
| As time | 9053 seconds = 2 h 30 min 53 s |
Is 9053 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (9053 ÷ 11 = 823) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 9053 a prime number?
No. 9053 = 11 × 823, so it is divisible by 11.
What are the factors of 9053?
1, 11, 823, 9053.
What is 9053 in binary?
10001101011101 (hexadecimal 235D, octal 21535).
What is the square root of 9053?
About 95.1473.
Is 9053 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 9053?
9053 is a semiprime: 11 × 823, the product of two primes.