The number 89401

No. 89401 = 13^2 × 23^2, so it is divisible by 13.

89401 is a perfect square (299²). Its prime factorisation is $13^{2}$ × $23^{2}$ . Divisors (9): 1, 13, 23, 169, 299, 529, 3887, 6877, 89401.

Number

Pick any whole number from 1 to 100,000.

89401 = 13^{2} \times 23^{2}

How to work it out

1
What is special about 89401: a perfect square (299²).
2
89401 is composite. Its prime factorisation is
$89401 = 13^{2} \times 23^{2}$
3
The divisors add up to 101199; without 89401 itself that is 11798, so 89401 is deficient (11798 is less than 89401). Euler's totient φ(89401) = 78936 numbers up to 89401 share no factor with it.
4
The digits of 89401 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 239 steps to reach 1.

LaTeX source of the formulas on this page

\[ 89401 = 13^{2} \times 23^{2} \]

Form	Value
In words	eighty-nine thousand four hundred and one
Binary (base 2)	10101110100111001
Octal (base 8)	256471
Hexadecimal (base 16)	15D39
Base 3	11112122011
As time	89401 seconds = 24 h 50 min 1 s

Divisor	Answer	Rule
2	No (remainder 1)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	No (remainder 1)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	No (remainder 1)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 1)	A number is divisible by 5 if the last digit is 0 or 5.
6	No (remainder 1)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 4)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	No (remainder 1)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 4)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 1)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 4)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	No (remainder 1)	A number is divisible by 12 if it is divisible by both 3 and 4.

Is 89401 a prime number?

No. 89401 = $13^{2}$ × $23^{2}$ , so it is divisible by 13.

What are the factors of 89401?

1, 13, 23, 169, 299, 529, 3887, 6877, 89401.

What is 89401 in binary?

10101110100111001 (hexadecimal 15D39, octal 256471).

What is the square root of 89401?

299, because 299 × 299 = 89401.

Is 89401 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 89401?

89401 is a perfect square (299²).