The number 87423
87423 is a composite number with 16 divisors. Its prime factorisation is 3 × 7 × 23 × 181. Divisors (16): 1, 3, 7, 21, 23, 69, 161, 181, 483, 543, 1267, 3801, 4163, 12489, 29141, 87423.
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How to work it out
- 1
87423 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
87423 is composite. Its prime factorisation is
- 3
The divisors add up to 139776; without 87423 itself that is 52353, so 87423 is deficient (52353 is less than 87423). Euler's totient φ(87423) = 47520 numbers up to 87423 share no factor with it.
- 4
The digits of 87423 add up to 24, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 133 steps to reach 1.
LaTeX source of the formulas on this page
\[ 87423 = 3 \times 7 \times 23 \times 181 \]
87423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 139776 |
| Euler totient φ(n) | 47520 |
| Square | 7642780929 |
| Cube | 668154837155967 |
| Square root | 295.673807 |
| Digit sum / digital root | 24 / 6 |
| Collatz steps to 1 | 133 |
| Scientific notation | 8.7423 × |
87423 in other forms
| Form | Value |
|---|---|
| In words | eighty-seven thousand four hundred and twenty-three |
| Binary (base 2) | 10101010101111111 |
| Octal (base 8) | 252577 |
| Hexadecimal (base 16) | 1557F |
| Base 3 | 11102220220 |
| As time | 87423 seconds = 24 h 17 min 3 s |
Is 87423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (87423 ÷ 3 = 29141) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (87423 ÷ 7 = 12489) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 87423 a prime number?
No. 87423 = 3 × 7 × 23 × 181, so it is divisible by 3.
What are the factors of 87423?
1, 3, 7, 21, 23, 69, 161, 181, 483, 543, 1267, 3801, 4163, 12489, 29141, 87423.
What is 87423 in binary?
10101010101111111 (hexadecimal 1557F, octal 252577).
What is the square root of 87423?
About 295.6738.
Is 87423 divisible by 3?
Yes. Its digits add up to 24, a multiple of 3.
What is special about the number 87423?
It is a composite number with 16 divisors.