The number 8423
8423 is the 1053rd prime number. Its only divisors are 1 and 8423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 8423: the 1053rd prime number.
- 2
8423 is prime, so its only factors are 1 and 8423. It is the 1053rd prime; the next prime is 8429 and the one before is 8419.
- 3
The divisors add up to 8424; without 8423 itself that is 1, so 8423 is deficient (1 is less than 8423). Euler's totient φ(8423) = 8422 numbers up to 8423 share no factor with it.
- 4
The digits of 8423 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 65 steps to reach 1.
8423 at a glance
| Property | Value |
|---|---|
| Type | prime |
| Number of divisors | 2 |
| Sum of divisors | 8424 |
| Euler totient φ(n) | 8422 |
| Square | 70946929 |
| Cube | 597585982967 |
| Square root | 91.776903 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 65 |
| Scientific notation | 8.423 × |
8423 in other forms
| Form | Value |
|---|---|
| In words | eight thousand four hundred and twenty-three |
| Binary (base 2) | 10000011100111 |
| Octal (base 8) | 20347 |
| Hexadecimal (base 16) | 20E7 |
| Base 3 | 102112222 |
| As time | 8423 seconds = 2 h 20 min 23 s |
Is 8423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 8423 a prime number?
Yes. 8423 is divisible only by 1 and itself.
What are the factors of 8423?
1, 8423.
What is 8423 in binary?
10000011100111 (hexadecimal 20E7, octal 20347).
What is the square root of 8423?
About 91.7769.
Is 8423 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 8423?
8423 is the 1053rd prime number.