The number 84013
84013 is a composite number with 4 divisors. Its prime factorisation is 29 × 2897. Divisors (4): 1, 29, 2897, 84013.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 84013: a semiprime: 29 × 2897, the product of two primes.
- 2
84013 is composite. Its prime factorisation is
- 3
The divisors add up to 86940; without 84013 itself that is 2927, so 84013 is deficient (2927 is less than 84013). Euler's totient φ(84013) = 81088 numbers up to 84013 share no factor with it.
- 4
The digits of 84013 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 133 steps to reach 1.
LaTeX source of the formulas on this page
\[ 84013 = 29 \times 2897 \]
84013 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 86940 |
| Euler totient φ(n) | 81088 |
| Square | 7058184169 |
| Cube | 592979226590197 |
| Square root | 289.849961 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 133 |
| Scientific notation | 8.4013 × |
84013 in other forms
| Form | Value |
|---|---|
| In words | eighty-four thousand and thirteen |
| Binary (base 2) | 10100100000101101 |
| Octal (base 8) | 244055 |
| Hexadecimal (base 16) | 1482D |
| Base 3 | 11021020121 |
| As time | 84013 seconds = 23 h 20 min 13 s |
Is 84013 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 84013 a prime number?
No. 84013 = 29 × 2897, so it is divisible by 29.
What are the factors of 84013?
1, 29, 2897, 84013.
What is 84013 in binary?
10100100000101101 (hexadecimal 1482D, octal 244055).
What is the square root of 84013?
About 289.8500.
Is 84013 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 84013?
84013 is a semiprime: 29 × 2897, the product of two primes.