The number 83983
83983 is the 8189th prime number. Its only divisors are 1 and 83983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 83983: the 8189th prime number.
- 2
83983 is prime, so its only factors are 1 and 83983. It is the 8189th prime; the next prime is 83987 and the one before is 83969.
- 3
The divisors add up to 83984; without 83983 itself that is 1, so 83983 is deficient (1 is less than 83983). Euler's totient φ(83983) = 83982 numbers up to 83983 share no factor with it.
- 4
The digits of 83983 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 120 steps to reach 1.
83983 at a glance
| Property | Value |
|---|---|
| Type | prime |
| Number of divisors | 2 |
| Sum of divisors | 83984 |
| Euler totient φ(n) | 83982 |
| Square | 7053144289 |
| Cube | 592344216823087 |
| Square root | 289.798206 |
| Digit sum / digital root | 31 / 4 |
| Collatz steps to 1 | 120 |
| Scientific notation | 8.3983 × |
83983 in other forms
| Form | Value |
|---|---|
| In words | eighty-three thousand nine hundred and eighty-three |
| Binary (base 2) | 10100100000001111 |
| Octal (base 8) | 244017 |
| Hexadecimal (base 16) | 1480F |
| Base 3 | 11021012111 |
| As time | 83983 seconds = 23 h 19 min 43 s |
Is 83983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 83983 a prime number?
Yes. 83983 is divisible only by 1 and itself.
What are the factors of 83983?
1, 83983.
What is 83983 in binary?
10100100000001111 (hexadecimal 1480F, octal 244017).
What is the square root of 83983?
About 289.7982.
Is 83983 divisible by 3?
No. Its digits add up to 31, which is not a multiple of 3.
What is special about the number 83983?
83983 is the 8189th prime number.