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The number 83937

83937 is a composite number with 12 divisors. Its prime factorisation is 3 × 727^{2} × 571. Divisors (12): 1, 3, 7, 21, 49, 147, 571, 1713, 3997, 11991, 27979, 83937.

Number

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How to work it out

  1. 1

    83937 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    83937 is composite. Its prime factorisation is

    83937=3×72×57183937 = 3 \times 7^{2} \times 571
  3. 3

    The divisors add up to 130416; without 83937 itself that is 46479, so 83937 is deficient (46479 is less than 83937). Euler's totient φ(83937) = 47880 numbers up to 83937 share no factor with it.

  4. 4

    The digits of 83937 add up to 30, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 94 steps to reach 1.

LaTeX source of the formulas on this page
\[ 83937 = 3 \times 7^{2} \times 571 \]

83937 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors130416
Euler totient φ(n)47880
Square7045419969
Cube591371415937953
Square root289.718829 (= 7√1713)
Digit sum / digital root30 / 3
Collatz steps to 194
Scientific notation8.3937 × 10410^{4}

83937 in other forms

FormValue
In wordseighty-three thousand nine hundred and thirty-seven
Binary (base 2)10100011111100001
Octal (base 8)243741
Hexadecimal (base 16)147E1
Base 311021010210
As time83937 seconds = 23 h 18 min 57 s

Is 83937 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (83937 ÷ 3 = 27979)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (83937 ÷ 7 = 11991)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 3)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 83937 a prime number?

No. 83937 = 3 × 727^{2} × 571, so it is divisible by 3.

What are the factors of 83937?

1, 3, 7, 21, 49, 147, 571, 1713, 3997, 11991, 27979, 83937.

What is 83937 in binary?

10100011111100001 (hexadecimal 147E1, octal 243741).

What is the square root of 83937?

About 289.7188, exactly 7√1713.

Is 83937 divisible by 3?

Yes. Its digits add up to 30, a multiple of 3.

What is special about the number 83937?

It is a composite number with 12 divisors.

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    83937: is it prime? Factors, square root, binary, Roman numeral | WordGPT