The number 83929
83929 is a composite number with 4 divisors. Its prime factorisation is 17 × 4937. Divisors (4): 1, 17, 4937, 83929.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 83929: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 17 × 4937, the product of two primes.
- 2
83929 is composite. Its prime factorisation is
- 3
The divisors add up to 88884; without 83929 itself that is 4955, so 83929 is deficient (4955 is less than 83929). Euler's totient φ(83929) = 78976 numbers up to 83929 share no factor with it.
- 4
The digits of 83929 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 151 steps to reach 1.
LaTeX source of the formulas on this page
\[ 83929 = 17 \times 4937 \]
83929 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 88884 |
| Euler totient φ(n) | 78976 |
| Square | 7044077041 |
| Cube | 591202341974089 |
| Square root | 289.705022 |
| Digit sum / digital root | 31 / 4 |
| Collatz steps to 1 | 151 |
| Scientific notation | 8.3929 × |
83929 in other forms
| Form | Value |
|---|---|
| In words | eighty-three thousand nine hundred and twenty-nine |
| Binary (base 2) | 10100011111011001 |
| Octal (base 8) | 243731 |
| Hexadecimal (base 16) | 147D9 |
| Base 3 | 11021010111 |
| As time | 83929 seconds = 23 h 18 min 49 s |
Is 83929 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 83929 a prime number?
No. 83929 = 17 × 4937, so it is divisible by 17.
What are the factors of 83929?
1, 17, 4937, 83929.
What is 83929 in binary?
10100011111011001 (hexadecimal 147D9, octal 243731).
What is the square root of 83929?
About 289.7050.
Is 83929 divisible by 3?
No. Its digits add up to 31, which is not a multiple of 3.
What is special about the number 83929?
83929 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 17 × 4937, the product of two primes.