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The number 83823

83823 is a composite number with 4 divisors. Its prime factorisation is 3 × 27941. Divisors (4): 1, 3, 27941, 83823.

Number

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How to work it out

  1. 1

    What is special about 83823: a semiprime: 3 × 27941, the product of two primes.

  2. 2

    83823 is composite. Its prime factorisation is

    83823=3×2794183823 = 3 \times 27941
  3. 3

    The divisors add up to 111768; without 83823 itself that is 27945, so 83823 is deficient (27945 is less than 83823). Euler's totient φ(83823) = 55880 numbers up to 83823 share no factor with it.

  4. 4

    The digits of 83823 add up to 24, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 89 steps to reach 1.

LaTeX source of the formulas on this page
\[ 83823 = 3 \times 27941 \]

83823 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors111768
Euler totient φ(n)55880
Square7026295329
Cube588965153362767
Square root289.522020
Digit sum / digital root24 / 6
Collatz steps to 189
Scientific notation8.3823 × 10410^{4}

83823 in other forms

FormValue
In wordseighty-three thousand eight hundred and twenty-three
Binary (base 2)10100011101101111
Octal (base 8)243557
Hexadecimal (base 16)1476F
Base 311020222120
As time83823 seconds = 23 h 17 min 3 s

Is 83823 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (83823 ÷ 3 = 27941)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 6)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 3)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 83823 a prime number?

No. 83823 = 3 × 27941, so it is divisible by 3.

What are the factors of 83823?

1, 3, 27941, 83823.

What is 83823 in binary?

10100011101101111 (hexadecimal 1476F, octal 243557).

What is the square root of 83823?

About 289.5220.

Is 83823 divisible by 3?

Yes. Its digits add up to 24, a multiple of 3.

What is special about the number 83823?

83823 is a semiprime: 3 × 27941, the product of two primes.

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