The number 83793
83793 is a composite number with 16 divisors. Its prime factorisation is 3 × 17 × 31 × 53. Divisors (16): 1, 3, 17, 31, 51, 53, 93, 159, 527, 901, 1581, 1643, 2703, 4929, 27931, 83793.
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How to work it out
- 1
83793 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
83793 is composite. Its prime factorisation is
- 3
The divisors add up to 124416; without 83793 itself that is 40623, so 83793 is deficient (40623 is less than 83793). Euler's totient φ(83793) = 49920 numbers up to 83793 share no factor with it.
- 4
The digits of 83793 add up to 30, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 89 steps to reach 1.
LaTeX source of the formulas on this page
\[ 83793 = 3 \times 17 \times 31 \times 53 \]
83793 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 124416 |
| Euler totient φ(n) | 49920 |
| Square | 7021266849 |
| Cube | 588333013078257 |
| Square root | 289.470206 |
| Digit sum / digital root | 30 / 3 |
| Collatz steps to 1 | 89 |
| Scientific notation | 8.3793 × |
83793 in other forms
| Form | Value |
|---|---|
| In words | eighty-three thousand seven hundred and ninety-three |
| Binary (base 2) | 10100011101010001 |
| Octal (base 8) | 243521 |
| Hexadecimal (base 16) | 14751 |
| Base 3 | 11020221110 |
| As time | 83793 seconds = 23 h 16 min 33 s |
Is 83793 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (83793 ÷ 3 = 27931) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 83793 a prime number?
No. 83793 = 3 × 17 × 31 × 53, so it is divisible by 3.
What are the factors of 83793?
1, 3, 17, 31, 51, 53, 93, 159, 527, 901, 1581, 1643, 2703, 4929, 27931, 83793.
What is 83793 in binary?
10100011101010001 (hexadecimal 14751, octal 243521).
What is the square root of 83793?
About 289.4702.
Is 83793 divisible by 3?
Yes. Its digits add up to 30, a multiple of 3.
What is special about the number 83793?
It is a composite number with 16 divisors.