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The number 83545

83545 is a composite number with 24 divisors. Its prime factorisation is 5 × 727^{2} × 11 × 31. Divisors (24): 1, 5, 7, 11, 31, 35, 49, 55, 77, 155, 217, 245, 341, 385, 539, 1085 … 83545.

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How to work it out

  1. 1

    What is special about 83545: a happy number: repeatedly adding the squares of its digits reaches 1.

  2. 2

    83545 is composite. Its prime factorisation is

    83545=5×72×11×3183545 = 5 \times 7^{2} \times 11 \times 31
  3. 3

    The divisors add up to 131328; without 83545 itself that is 47783, so 83545 is deficient (47783 is less than 83545). Euler's totient φ(83545) = 50400 numbers up to 83545 share no factor with it.

  4. 4

    The digits of 83545 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 63 steps to reach 1.

LaTeX source of the formulas on this page
\[ 83545 = 5 \times 7^{2} \times 11 \times 31 \]

83545 at a glance

PropertyValue
Typecomposite
Number of divisors24
Sum of divisors131328
Euler totient φ(n)50400
Square6979767025
Cube583124636103625
Square root289.041520 (= 7√1705)
Digit sum / digital root25 / 7
Collatz steps to 163
Scientific notation8.3545 × 10410^{4}

83545 in other forms

FormValue
In wordseighty-three thousand five hundred and forty-five
Binary (base 2)10100011001011001
Octal (base 8)243131
Hexadecimal (base 16)14659
Base 311020121021
As time83545 seconds = 23 h 12 min 25 s

Is 83545 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (83545 ÷ 5 = 16709)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (83545 ÷ 7 = 11935)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11Yes (83545 ÷ 11 = 7595)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 83545 a prime number?

No. 83545 = 5 × 727^{2} × 11 × 31, so it is divisible by 5.

What are the factors of 83545?

1, 5, 7, 11, 31, 35, 49, 55, 77, 155, 217, 245, 341, 385, 539, 1085, 1519, 1705, 2387, 2695, 7595, 11935, 16709, 83545.

What is 83545 in binary?

10100011001011001 (hexadecimal 14659, octal 243131).

What is the square root of 83545?

About 289.0415, exactly 7√1705.

Is 83545 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 83545?

83545 is a happy number: repeatedly adding the squares of its digits reaches 1.

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