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The number 83223

83223 is a composite number with 12 divisors. Its prime factorisation is 323^{2} × 7 × 1321. Divisors (12): 1, 3, 7, 9, 21, 63, 1321, 3963, 9247, 11889, 27741, 83223.

Number

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How to work it out

  1. 1

    83223 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    83223 is composite. Its prime factorisation is

    83223=32×7×132183223 = 3^{2} \times 7 \times 1321
  3. 3

    The divisors add up to 137488; without 83223 itself that is 54265, so 83223 is deficient (54265 is less than 83223). Euler's totient φ(83223) = 47520 numbers up to 83223 share no factor with it.

  4. 4

    The digits of 83223 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 151 steps to reach 1.

LaTeX source of the formulas on this page
\[ 83223 = 3^{2} \times 7 \times 1321 \]

83223 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors137488
Euler totient φ(n)47520
Square6926067729
Cube576408134610567
Square root288.483968 (= 3√9247)
Digit sum / digital root18 / 9
Collatz steps to 1151
Scientific notation8.3223 × 10410^{4}

83223 in other forms

FormValue
In wordseighty-three thousand two hundred and twenty-three
Binary (base 2)10100010100010111
Octal (base 8)242427
Hexadecimal (base 16)14517
Base 311020011100
As time83223 seconds = 23 h 7 min 3 s

Is 83223 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (83223 ÷ 3 = 27741)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (83223 ÷ 7 = 11889)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (83223 ÷ 9 = 9247)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 83223 a prime number?

No. 83223 = 323^{2} × 7 × 1321, so it is divisible by 3.

What are the factors of 83223?

1, 3, 7, 9, 21, 63, 1321, 3963, 9247, 11889, 27741, 83223.

What is 83223 in binary?

10100010100010111 (hexadecimal 14517, octal 242427).

What is the square root of 83223?

About 288.4840, exactly 3√9247.

Is 83223 divisible by 3?

Yes. Its digits add up to 18, a multiple of 3.

What is special about the number 83223?

It is a composite number with 12 divisors.

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    83223: is it prime? Factors, square root, binary, Roman numeral | WordGPT