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The number 82953

82953 is a composite number with 12 divisors. Its prime factorisation is 323^{2} × 13 × 709. Divisors (12): 1, 3, 9, 13, 39, 117, 709, 2127, 6381, 9217, 27651, 82953.

Number

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How to work it out

  1. 1

    82953 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    82953 is composite. Its prime factorisation is

    82953=32×13×70982953 = 3^{2} \times 13 \times 709
  3. 3

    The divisors add up to 129220; without 82953 itself that is 46267, so 82953 is deficient (46267 is less than 82953). Euler's totient φ(82953) = 50976 numbers up to 82953 share no factor with it.

  4. 4

    The digits of 82953 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 151 steps to reach 1.

LaTeX source of the formulas on this page
\[ 82953 = 3^{2} \times 13 \times 709 \]

82953 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors129220
Euler totient φ(n)50976
Square6881200209
Cube570816200937177
Square root288.015625 (= 3√9217)
Digit sum / digital root27 / 9
Collatz steps to 1151
Scientific notation8.2953 × 10410^{4}

82953 in other forms

FormValue
In wordseighty-two thousand nine hundred and fifty-three
Binary (base 2)10100010000001001
Octal (base 8)242011
Hexadecimal (base 16)14409
Base 311012210100
As time82953 seconds = 23 h 2 min 33 s

Is 82953 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (82953 ÷ 3 = 27651)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (82953 ÷ 9 = 9217)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 2)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 82953 a prime number?

No. 82953 = 323^{2} × 13 × 709, so it is divisible by 3.

What are the factors of 82953?

1, 3, 9, 13, 39, 117, 709, 2127, 6381, 9217, 27651, 82953.

What is 82953 in binary?

10100010000001001 (hexadecimal 14409, octal 242011).

What is the square root of 82953?

About 288.0156, exactly 3√9217.

Is 82953 divisible by 3?

Yes. Its digits add up to 27, a multiple of 3.

What is special about the number 82953?

It is a composite number with 12 divisors.

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