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The number 82825

82825 is a composite number with 6 divisors. Its prime factorisation is 525^{2} Ɨ 3313. Divisors (6): 1, 5, 25, 3313, 16565, 82825.

Number

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How to work it out

  1. 1

    What is special about 82825: a Harshad number: divisible by its digit sum 25.

  2. 2

    82825 is composite. Its prime factorisation is

    82825=52Ɨ331382825 = 5^{2} \times 3313
  3. 3

    The divisors add up to 102734; without 82825 itself that is 19909, so 82825 is deficient (19909 is less than 82825). Euler's totient φ(82825) = 66240 numbers up to 82825 share no factor with it.

  4. 4

    The digits of 82825 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 120 steps to reach 1.

LaTeX source of the formulas on this page
\[ 82825 = 5^{2} \times 3313 \]

82825 at a glance

PropertyValue
Typecomposite
Number of divisors6
Sum of divisors102734
Euler totient φ(n)66240
Square6859980625
Cube568177895265625
Square root287.793329 (= 5√3313)
Digit sum / digital root25 / 7
Collatz steps to 1120
Scientific notation8.2825 Ɨ 10410^{4}

82825 in other forms

FormValue
In wordseighty-two thousand eight hundred and twenty-five
Binary (base 2)10100001110001001
Octal (base 8)241611
Hexadecimal (base 16)14389
Base 311012121121
As time82825 seconds = 23 h 0 min 25 s

Is 82825 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (82825 Ć· 5 = 16565)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 82825 a prime number?

No. 82825 = 525^{2} Ɨ 3313, so it is divisible by 5.

What are the factors of 82825?

1, 5, 25, 3313, 16565, 82825.

What is 82825 in binary?

10100001110001001 (hexadecimal 14389, octal 241611).

What is the square root of 82825?

About 287.7933, exactly 5√3313.

Is 82825 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 82825?

82825 is a Harshad number: divisible by its digit sum 25.

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    82825: is it prime? Factors, square root, binary, Roman numeral | WordGPT