The number 82429
82429 is a composite number with 4 divisors. Its prime factorisation is 31 × 2659. Divisors (4): 1, 31, 2659, 82429.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 82429: a semiprime: 31 × 2659, the product of two primes.
- 2
82429 is composite. Its prime factorisation is
- 3
The divisors add up to 85120; without 82429 itself that is 2691, so 82429 is deficient (2691 is less than 82429). Euler's totient φ(82429) = 79740 numbers up to 82429 share no factor with it.
- 4
The digits of 82429 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 94 steps to reach 1.
LaTeX source of the formulas on this page
\[ 82429 = 31 \times 2659 \]
82429 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 85120 |
| Euler totient φ(n) | 79740 |
| Square | 6794540041 |
| Cube | 560067141039589 |
| Square root | 287.104511 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 94 |
| Scientific notation | 8.2429 × |
82429 in other forms
| Form | Value |
|---|---|
| In words | eighty-two thousand four hundred and twenty-nine |
| Binary (base 2) | 10100000111111101 |
| Octal (base 8) | 240775 |
| Hexadecimal (base 16) | 141FD |
| Base 3 | 11012001221 |
| As time | 82429 seconds = 22 h 53 min 49 s |
Is 82429 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 82429 a prime number?
No. 82429 = 31 × 2659, so it is divisible by 31.
What are the factors of 82429?
1, 31, 2659, 82429.
What is 82429 in binary?
10100000111111101 (hexadecimal 141FD, octal 240775).
What is the square root of 82429?
About 287.1045.
Is 82429 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 82429?
82429 is a semiprime: 31 × 2659, the product of two primes.