The number 82113
82113 is a composite number with 8 divisors. Its prime factorisation is 3 × 101 × 271. Divisors (8): 1, 3, 101, 271, 303, 813, 27371, 82113.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 82113: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
82113 is composite. Its prime factorisation is
- 3
The divisors add up to 110976; without 82113 itself that is 28863, so 82113 is deficient (28863 is less than 82113). Euler's totient φ(82113) = 54000 numbers up to 82113 share no factor with it.
- 4
The digits of 82113 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 182 steps to reach 1.
LaTeX source of the formulas on this page
\[ 82113 = 3 \times 101 \times 271 \]
82113 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 110976 |
| Euler totient φ(n) | 54000 |
| Square | 6742544769 |
| Cube | 553650578616897 |
| Square root | 286.553660 |
| Digit sum / digital root | 15 / 6 |
| Collatz steps to 1 | 182 |
| Scientific notation | 8.2113 × |
82113 in other forms
| Form | Value |
|---|---|
| In words | eighty-two thousand one hundred and thirteen |
| Binary (base 2) | 10100000011000001 |
| Octal (base 8) | 240301 |
| Hexadecimal (base 16) | 140C1 |
| Base 3 | 11011122020 |
| As time | 82113 seconds = 22 h 48 min 33 s |
Is 82113 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (82113 ÷ 3 = 27371) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 82113 a prime number?
No. 82113 = 3 × 101 × 271, so it is divisible by 3.
What are the factors of 82113?
1, 3, 101, 271, 303, 813, 27371, 82113.
What is 82113 in binary?
10100000011000001 (hexadecimal 140C1, octal 240301).
What is the square root of 82113?
About 286.5537.
Is 82113 divisible by 3?
Yes. Its digits add up to 15, a multiple of 3.
What is special about the number 82113?
82113 is a happy number: repeatedly adding the squares of its digits reaches 1.