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The number 80850

80850 is a composite number with 72 divisors. Its prime factorisation is 2 × 3 × 525^{2} × 727^{2} × 11. Divisors (72): 1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 25, 30, 33, 35 … 80850.

Number

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How to work it out

  1. 1

    What is special about 80850: a Harshad number: divisible by its digit sum 21.

  2. 2

    80850 is composite. Its prime factorisation is

    80850=2×3×52×72×1180850 = 2 \times 3 \times 5^{2} \times 7^{2} \times 11
  3. 3

    The divisors add up to 254448; without 80850 itself that is 173598, so 80850 is abundant (173598 is more than 80850). Euler's totient φ(80850) = 16800 numbers up to 80850 share no factor with it.

  4. 4

    The digits of 80850 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 182 steps to reach 1.

LaTeX source of the formulas on this page
\[ 80850 = 2 \times 3 \times 5^{2} \times 7^{2} \times 11 \]

80850 at a glance

PropertyValue
Typecomposite
Number of divisors72
Sum of divisors254448
Euler totient φ(n)16800
Square6536722500
Cube528494014125000
Square root284.341344 (= 35√66)
Digit sum / digital root21 / 3
Collatz steps to 1182
Scientific notation8.085 × 10410^{4}

80850 in other forms

FormValue
In wordseighty thousand eight hundred and fifty
Binary (base 2)10011101111010010
Octal (base 8)235722
Hexadecimal (base 16)13BD2
Base 311002220110
As time80850 seconds = 22 h 27 min 30 s

Is 80850 divisible by 2 to 12?

DivisorAnswerRule
2Yes (80850 ÷ 2 = 40425)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (80850 ÷ 3 = 26950)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 2)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (80850 ÷ 5 = 16170)A number is divisible by 5 if the last digit is 0 or 5.
6Yes (80850 ÷ 6 = 13475)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (80850 ÷ 7 = 11550)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 2)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 3)A number is divisible by 9 if the digits add up to a multiple of 9.
10Yes (80850 ÷ 10 = 8085)A number is divisible by 10 if the last digit is 0.
11Yes (80850 ÷ 11 = 7350)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 6)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 80850 a prime number?

No. 80850 = 2 × 3 × 525^{2} × 727^{2} × 11, so it is divisible by 2.

What are the factors of 80850?

1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 25, 30, 33, 35, 42, 49, 50, 55, 66, 70, 75, 77, 98, 105, 110, 147, 150, 154, 165, 175, 210, 231, 245, 275, 294, 330, 350, 385, 462, 490, 525, 539, 550, 735, 770, 825, 1050, 1078, 1155, 1225, 1470, 1617, 1650, 1925, 2310, 2450, 2695, 3234, 3675, 3850, 5390, 5775, 7350, 8085, 11550, 13475, 16170, 26950, 40425, 80850.

What is 80850 in binary?

10011101111010010 (hexadecimal 13BD2, octal 235722).

What is the square root of 80850?

About 284.3413, exactly 35√66.

Is 80850 divisible by 3?

Yes. Its digits add up to 21, a multiple of 3.

What is special about the number 80850?

80850 is a Harshad number: divisible by its digit sum 21.

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