The number 80793
80793 is a composite number with 12 divisors. Its prime factorisation is × 47 × 191. Divisors (12): 1, 3, 9, 47, 141, 191, 423, 573, 1719, 8977, 26931, 80793.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80793: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
80793 is composite. Its prime factorisation is
- 3
The divisors add up to 119808; without 80793 itself that is 39015, so 80793 is deficient (39015 is less than 80793). Euler's totient φ(80793) = 52440 numbers up to 80793 share no factor with it.
- 4
The digits of 80793 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 89 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80793 = 3^{2} \times 47 \times 191 \]80793 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 119808 |
| Euler totient φ(n) | 52440 |
| Square | 6527508849 |
| Cube | 527377022437257 |
| Square root | 284.241095 (= 3√8977) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 89 |
| Scientific notation | 8.0793 × |
80793 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand seven hundred and ninety-three |
| Binary (base 2) | 10011101110011001 |
| Octal (base 8) | 235631 |
| Hexadecimal (base 16) | 13B99 |
| Base 3 | 11002211100 |
| As time | 80793 seconds = 22 h 26 min 33 s |
Is 80793 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (80793 ÷ 3 = 26931) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (80793 ÷ 9 = 8977) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80793 a prime number?
No. 80793 = × 47 × 191, so it is divisible by 3.
What are the factors of 80793?
1, 3, 9, 47, 141, 191, 423, 573, 1719, 8977, 26931, 80793.
What is 80793 in binary?
10011101110011001 (hexadecimal 13B99, octal 235631).
What is the square root of 80793?
About 284.2411, exactly 3√8977.
Is 80793 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 80793?
80793 is a happy number: repeatedly adding the squares of its digits reaches 1.