The number 80473
80473 is a twin prime (80471 and 80473 are both prime) and the 7877th prime number. Its only divisors are 1 and 80473.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80473: a twin prime (80471 and 80473 are both prime); the 7877th prime number.
- 2
80473 is prime, so its only factors are 1 and 80473. It is the 7877th prime; the next prime is 80489 and the one before is 80471.
- 3
The divisors add up to 80474; without 80473 itself that is 1, so 80473 is deficient (1 is less than 80473). Euler's totient φ(80473) = 80472 numbers up to 80473 share no factor with it.
- 4
The digits of 80473 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 151 steps to reach 1.
80473 at a glance
| Property | Value |
|---|---|
| Type | prime |
| Number of divisors | 2 |
| Sum of divisors | 80474 |
| Euler totient φ(n) | 80472 |
| Square | 6475903729 |
| Cube | 521135400783817 |
| Square root | 283.677634 |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 151 |
| Scientific notation | 8.0473 × |
80473 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand four hundred and seventy-three |
| Binary (base 2) | 10011101001011001 |
| Octal (base 8) | 235131 |
| Hexadecimal (base 16) | 13A59 |
| Base 3 | 11002101111 |
| As time | 80473 seconds = 22 h 21 min 13 s |
Is 80473 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80473 a prime number?
Yes. 80473 is divisible only by 1 and itself.
What are the factors of 80473?
1, 80473.
What is 80473 in binary?
10011101001011001 (hexadecimal 13A59, octal 235131).
What is the square root of 80473?
About 283.6776.
Is 80473 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 80473?
80473 is a twin prime (80471 and 80473 are both prime); the 7877th prime number.