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The number 80433

80433 is a composite number with 12 divisors. Its prime factorisation is 353^{5} × 331. Divisors (12): 1, 3, 9, 27, 81, 243, 331, 993, 2979, 8937, 26811, 80433.

Number

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How to work it out

  1. 1

    80433 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    80433 is composite. Its prime factorisation is

    80433=35×33180433 = 3^{5} \times 331
  3. 3

    The divisors add up to 120848; without 80433 itself that is 40415, so 80433 is deficient (40415 is less than 80433). Euler's totient φ(80433) = 53460 numbers up to 80433 share no factor with it.

  4. 4

    The digits of 80433 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 94 steps to reach 1.

LaTeX source of the formulas on this page
\[ 80433 = 3^{5} \times 331 \]

80433 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors120848
Euler totient φ(n)53460
Square6469467489
Cube520358678542737
Square root283.607123 (= 9√993)
Digit sum / digital root18 / 9
Collatz steps to 194
Scientific notation8.0433 × 10410^{4}

80433 in other forms

FormValue
In wordseighty thousand four hundred and thirty-three
Binary (base 2)10011101000110001
Octal (base 8)235061
Hexadecimal (base 16)13A31
Base 311002100000
As time80433 seconds = 22 h 20 min 33 s

Is 80433 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (80433 ÷ 3 = 26811)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (80433 ÷ 9 = 8937)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 1)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 80433 a prime number?

No. 80433 = 353^{5} × 331, so it is divisible by 3.

What are the factors of 80433?

1, 3, 9, 27, 81, 243, 331, 993, 2979, 8937, 26811, 80433.

What is 80433 in binary?

10011101000110001 (hexadecimal 13A31, octal 235061).

What is the square root of 80433?

About 283.6071, exactly 9√993.

Is 80433 divisible by 3?

Yes. Its digits add up to 18, a multiple of 3.

What is special about the number 80433?

It is a composite number with 12 divisors.

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