The number 80413
80413 is a composite number with 4 divisors. Its prime factorisation is 97 × 829. Divisors (4): 1, 97, 829, 80413.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80413: a semiprime: 97 × 829, the product of two primes.
- 2
80413 is composite. Its prime factorisation is
- 3
The divisors add up to 81340; without 80413 itself that is 927, so 80413 is deficient (927 is less than 80413). Euler's totient φ(80413) = 79488 numbers up to 80413 share no factor with it.
- 4
The digits of 80413 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 120 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80413 = 97 \times 829 \]
80413 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 81340 |
| Euler totient φ(n) | 79488 |
| Square | 6466250569 |
| Cube | 519970607004997 |
| Square root | 283.571860 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 120 |
| Scientific notation | 8.0413 × |
80413 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand four hundred and thirteen |
| Binary (base 2) | 10011101000011101 |
| Octal (base 8) | 235035 |
| Hexadecimal (base 16) | 13A1D |
| Base 3 | 11002022021 |
| As time | 80413 seconds = 22 h 20 min 13 s |
Is 80413 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80413 a prime number?
No. 80413 = 97 × 829, so it is divisible by 97.
What are the factors of 80413?
1, 97, 829, 80413.
What is 80413 in binary?
10011101000011101 (hexadecimal 13A1D, octal 235035).
What is the square root of 80413?
About 283.5719.
Is 80413 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 80413?
80413 is a semiprime: 97 × 829, the product of two primes.