The number 80397
80397 is a composite number with 6 divisors. Its prime factorisation is × 8933. Divisors (6): 1, 3, 9, 8933, 26799, 80397.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80397: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
80397 is composite. Its prime factorisation is
- 3
The divisors add up to 116142; without 80397 itself that is 35745, so 80397 is deficient (35745 is less than 80397). Euler's totient φ(80397) = 53592 numbers up to 80397 share no factor with it.
- 4
The digits of 80397 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 138 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80397 = 3^{2} \times 8933 \]80397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 116142 |
| Euler totient φ(n) | 53592 |
| Square | 6463677609 |
| Cube | 519660288730773 |
| Square root | 283.543647 (= 3√8933) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 138 |
| Scientific notation | 8.0397 × |
80397 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand three hundred and ninety-seven |
| Binary (base 2) | 10011101000001101 |
| Octal (base 8) | 235015 |
| Hexadecimal (base 16) | 13A0D |
| Base 3 | 11002021200 |
| As time | 80397 seconds = 22 h 19 min 57 s |
Is 80397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (80397 ÷ 3 = 26799) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (80397 ÷ 9 = 8933) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80397 a prime number?
No. 80397 = × 8933, so it is divisible by 3.
What are the factors of 80397?
1, 3, 9, 8933, 26799, 80397.
What is 80397 in binary?
10011101000001101 (hexadecimal 13A0D, octal 235015).
What is the square root of 80397?
About 283.5436, exactly 3√8933.
Is 80397 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 80397?
80397 is a happy number: repeatedly adding the squares of its digits reaches 1.