The number 80339
80339 is a composite number with 8 divisors. Its prime factorisation is 7 × 23 × 499. Divisors (8): 1, 7, 23, 161, 499, 3493, 11477, 80339.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80339: a Harshad number: divisible by its digit sum 23.
- 2
80339 is composite. Its prime factorisation is
- 3
The divisors add up to 96000; without 80339 itself that is 15661, so 80339 is deficient (15661 is less than 80339). Euler's totient φ(80339) = 65736 numbers up to 80339 share no factor with it.
- 4
The digits of 80339 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 76 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80339 = 7 \times 23 \times 499 \]
80339 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 96000 |
| Euler totient φ(n) | 65736 |
| Square | 6454354921 |
| Cube | 518536419998219 |
| Square root | 283.441352 |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 76 |
| Scientific notation | 8.0339 × |
80339 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand three hundred and thirty-nine |
| Binary (base 2) | 10011100111010011 |
| Octal (base 8) | 234723 |
| Hexadecimal (base 16) | 139D3 |
| Base 3 | 11002012112 |
| As time | 80339 seconds = 22 h 18 min 59 s |
Is 80339 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (80339 ÷ 7 = 11477) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80339 a prime number?
No. 80339 = 7 × 23 × 499, so it is divisible by 7.
What are the factors of 80339?
1, 7, 23, 161, 499, 3493, 11477, 80339.
What is 80339 in binary?
10011100111010011 (hexadecimal 139D3, octal 234723).
What is the square root of 80339?
About 283.4414.
Is 80339 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 80339?
80339 is a Harshad number: divisible by its digit sum 23.