The number 8023
8023 is a composite number with 4 divisors. Its prime factorisation is 71 × 113. Divisors (4): 1, 71, 113, 8023.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 8023: a semiprime: 71 × 113, the product of two primes.
- 2
8023 is composite. Its prime factorisation is
- 3
The divisors add up to 8208; without 8023 itself that is 185, so 8023 is deficient (185 is less than 8023). Euler's totient φ(8023) = 7840 numbers up to 8023 share no factor with it.
- 4
The digits of 8023 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 189 steps to reach 1.
LaTeX source of the formulas on this page
\[ 8023 = 71 \times 113 \]
8023 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 8208 |
| Euler totient φ(n) | 7840 |
| Square | 64368529 |
| Cube | 516428708167 |
| Square root | 89.571201 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 189 |
| Scientific notation | 8.023 × |
8023 in other forms
| Form | Value |
|---|---|
| In words | eight thousand and twenty-three |
| Binary (base 2) | 1111101010111 |
| Octal (base 8) | 17527 |
| Hexadecimal (base 16) | 1F57 |
| Base 3 | 102000011 |
| As time | 8023 seconds = 2 h 13 min 43 s |
Is 8023 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 8023 a prime number?
No. 8023 = 71 × 113, so it is divisible by 71.
What are the factors of 8023?
1, 71, 113, 8023.
What is 8023 in binary?
1111101010111 (hexadecimal 1F57, octal 17527).
What is the square root of 8023?
About 89.5712.
Is 8023 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 8023?
8023 is a semiprime: 71 × 113, the product of two primes.