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The number 80215

80215 is a composite number with 8 divisors. Its prime factorisation is 5 × 61 × 263. Divisors (8): 1, 5, 61, 263, 305, 1315, 16043, 80215.

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How to work it out

  1. 1

    What is special about 80215: a happy number: repeatedly adding the squares of its digits reaches 1.

  2. 2

    80215 is composite. Its prime factorisation is

    80215=5×61×26380215 = 5 \times 61 \times 263
  3. 3

    The divisors add up to 98208; without 80215 itself that is 17993, so 80215 is deficient (17993 is less than 80215). Euler's totient φ(80215) = 62880 numbers up to 80215 share no factor with it.

  4. 4

    The digits of 80215 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 94 steps to reach 1.

LaTeX source of the formulas on this page
\[ 80215 = 5 \times 61 \times 263 \]

80215 at a glance

PropertyValue
Typecomposite
Number of divisors8
Sum of divisors98208
Euler totient φ(n)62880
Square6434446225
Cube516139103938375
Square root283.222527
Digit sum / digital root16 / 7
Collatz steps to 194
Scientific notation8.0215 × 10410^{4}

80215 in other forms

FormValue
In wordseighty thousand two hundred and fifteen
Binary (base 2)10011100101010111
Octal (base 8)234527
Hexadecimal (base 16)13957
Base 311002000221
As time80215 seconds = 22 h 16 min 55 s

Is 80215 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (80215 ÷ 5 = 16043)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11No (remainder 3)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 80215 a prime number?

No. 80215 = 5 × 61 × 263, so it is divisible by 5.

What are the factors of 80215?

1, 5, 61, 263, 305, 1315, 16043, 80215.

What is 80215 in binary?

10011100101010111 (hexadecimal 13957, octal 234527).

What is the square root of 80215?

About 283.2225.

Is 80215 divisible by 3?

No. Its digits add up to 16, which is not a multiple of 3.

What is special about the number 80215?

80215 is a happy number: repeatedly adding the squares of its digits reaches 1.

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