The number 80003
80003 is a composite number with 8 divisors. Its prime factorisation is 7 × 11 × 1039. Divisors (8): 1, 7, 11, 77, 1039, 7273, 11429, 80003.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80003: a Harshad number: divisible by its digit sum 11.
- 2
80003 is composite. Its prime factorisation is
- 3
The divisors add up to 99840; without 80003 itself that is 19837, so 80003 is deficient (19837 is less than 80003). Euler's totient φ(80003) = 62280 numbers up to 80003 share no factor with it.
- 4
The digits of 80003 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 169 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80003 = 7 \times 11 \times 1039 \]
80003 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 99840 |
| Euler totient φ(n) | 62280 |
| Square | 6400480009 |
| Cube | 512057602160027 |
| Square root | 282.848016 |
| Digit sum / digital root | 11 / 2 |
| Collatz steps to 1 | 169 |
| Scientific notation | 8.0003 × |
80003 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand and three |
| Binary (base 2) | 10011100010000011 |
| Octal (base 8) | 234203 |
| Hexadecimal (base 16) | 13883 |
| Base 3 | 11001202002 |
| As time | 80003 seconds = 22 h 13 min 23 s |
Is 80003 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (80003 ÷ 7 = 11429) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (80003 ÷ 11 = 7273) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80003 a prime number?
No. 80003 = 7 × 11 × 1039, so it is divisible by 7.
What are the factors of 80003?
1, 7, 11, 77, 1039, 7273, 11429, 80003.
What is 80003 in binary?
10011100010000011 (hexadecimal 13883, octal 234203).
What is the square root of 80003?
About 282.8480.
Is 80003 divisible by 3?
No. Its digits add up to 11, which is not a multiple of 3.
What is special about the number 80003?
80003 is a Harshad number: divisible by its digit sum 11.