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The number 77953

77953 is a composite number with 4 divisors. Its prime factorisation is 137 × 569. Divisors (4): 1, 137, 569, 77953.

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How to work it out

  1. 1

    What is special about 77953: a semiprime: 137 × 569, the product of two primes.

  2. 2

    77953 is composite. Its prime factorisation is

    77953=137×56977953 = 137 \times 569
  3. 3

    The divisors add up to 78660; without 77953 itself that is 707, so 77953 is deficient (707 is less than 77953). Euler's totient φ(77953) = 77248 numbers up to 77953 share no factor with it.

  4. 4

    The digits of 77953 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 200 steps to reach 1.

LaTeX source of the formulas on this page
\[ 77953 = 137 \times 569 \]

77953 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors78660
Euler totient φ(n)77248
Square6076670209
Cube473694672802177
Square root279.200645
Digit sum / digital root31 / 4
Collatz steps to 1200
Scientific notation7.7953 × 10410^{4}

77953 in other forms

FormValue
In wordsseventy-seven thousand nine hundred and fifty-three
Binary (base 2)10011000010000001
Octal (base 8)230201
Hexadecimal (base 16)13081
Base 310221221011
As time77953 seconds = 21 h 39 min 13 s

Is 77953 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 77953 a prime number?

No. 77953 = 137 × 569, so it is divisible by 137.

What are the factors of 77953?

1, 137, 569, 77953.

What is 77953 in binary?

10011000010000001 (hexadecimal 13081, octal 230201).

What is the square root of 77953?

About 279.2006.

Is 77953 divisible by 3?

No. Its digits add up to 31, which is not a multiple of 3.

What is special about the number 77953?

77953 is a semiprime: 137 × 569, the product of two primes.

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