The number 76477
76477 is a composite number with 4 divisors. Its prime factorisation is 31 × 2467. Divisors (4): 1, 31, 2467, 76477.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 76477: a Harshad number: divisible by its digit sum 31; a semiprime: 31 × 2467, the product of two primes.
- 2
76477 is composite. Its prime factorisation is
- 3
The divisors add up to 78976; without 76477 itself that is 2499, so 76477 is deficient (2499 is less than 76477). Euler's totient φ(76477) = 73980 numbers up to 76477 share no factor with it.
- 4
The digits of 76477 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 81 steps to reach 1.
LaTeX source of the formulas on this page
\[ 76477 = 31 \times 2467 \]
76477 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 78976 |
| Euler totient φ(n) | 73980 |
| Square | 5848731529 |
| Cube | 447293441143333 |
| Square root | 276.544752 |
| Digit sum / digital root | 31 / 4 |
| Collatz steps to 1 | 81 |
| Scientific notation | 7.6477 × |
76477 in other forms
| Form | Value |
|---|---|
| In words | seventy-six thousand four hundred and seventy-seven |
| Binary (base 2) | 10010101010111101 |
| Octal (base 8) | 225275 |
| Hexadecimal (base 16) | 12ABD |
| Base 3 | 10212220111 |
| As time | 76477 seconds = 21 h 14 min 37 s |
Is 76477 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 76477 a prime number?
No. 76477 = 31 × 2467, so it is divisible by 31.
What are the factors of 76477?
1, 31, 2467, 76477.
What is 76477 in binary?
10010101010111101 (hexadecimal 12ABD, octal 225275).
What is the square root of 76477?
About 276.5448.
Is 76477 divisible by 3?
No. Its digits add up to 31, which is not a multiple of 3.
What is special about the number 76477?
76477 is a Harshad number: divisible by its digit sum 31; a semiprime: 31 × 2467, the product of two primes.