The number 76397
76397 is a composite number with 4 divisors. Its prime factorisation is 241 × 317. Divisors (4): 1, 241, 317, 76397.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 76397: a semiprime: 241 × 317, the product of two primes.
- 2
76397 is composite. Its prime factorisation is
- 3
The divisors add up to 76956; without 76397 itself that is 559, so 76397 is deficient (559 is less than 76397). Euler's totient φ(76397) = 75840 numbers up to 76397 share no factor with it.
- 4
The digits of 76397 add up to 32, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 138 steps to reach 1.
LaTeX source of the formulas on this page
\[ 76397 = 241 \times 317 \]
76397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 76956 |
| Euler totient φ(n) | 75840 |
| Square | 5836501609 |
| Cube | 445891213422773 |
| Square root | 276.400072 |
| Digit sum / digital root | 32 / 5 |
| Collatz steps to 1 | 138 |
| Scientific notation | 7.6397 × |
76397 in other forms
| Form | Value |
|---|---|
| In words | seventy-six thousand three hundred and ninety-seven |
| Binary (base 2) | 10010101001101101 |
| Octal (base 8) | 225155 |
| Hexadecimal (base 16) | 12A6D |
| Base 3 | 10212210112 |
| As time | 76397 seconds = 21 h 13 min 17 s |
Is 76397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 76397 a prime number?
No. 76397 = 241 × 317, so it is divisible by 241.
What are the factors of 76397?
1, 241, 317, 76397.
What is 76397 in binary?
10010101001101101 (hexadecimal 12A6D, octal 225155).
What is the square root of 76397?
About 276.4001.
Is 76397 divisible by 3?
No. Its digits add up to 32, which is not a multiple of 3.
What is special about the number 76397?
76397 is a semiprime: 241 × 317, the product of two primes.