The number 73508
73508 is a composite number with 24 divisors. Its prime factorisation is × 17 × 23 × 47. Divisors (24): 1, 2, 4, 17, 23, 34, 46, 47, 68, 92, 94, 188, 391, 782, 799, 1081 … 73508.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 73508: a Harshad number: divisible by its digit sum 23.
- 2
73508 is composite. Its prime factorisation is
- 3
The divisors add up to 145152; without 73508 itself that is 71644, so 73508 is deficient (71644 is less than 73508). Euler's totient φ(73508) = 32384 numbers up to 73508 share no factor with it.
- 4
The digits of 73508 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 156 steps to reach 1.
LaTeX source of the formulas on this page
\[ 73508 = 2^{2} \times 17 \times 23 \times 47 \]73508 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 24 |
| Sum of divisors | 145152 |
| Euler totient φ(n) | 32384 |
| Square | 5403426064 |
| Cube | 397195043112512 |
| Square root | 271.123588 (= 2√18377) |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 156 |
| Scientific notation | 7.3508 × |
73508 in other forms
| Form | Value |
|---|---|
| In words | seventy-three thousand five hundred and eight |
| Binary (base 2) | 10001111100100100 |
| Octal (base 8) | 217444 |
| Hexadecimal (base 16) | 11F24 |
| Base 3 | 10201211112 |
| As time | 73508 seconds = 20 h 25 min 8 s |
Is 73508 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (73508 ÷ 2 = 36754) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (73508 ÷ 4 = 18377) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 2) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 4) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 8) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 73508 a prime number?
No. 73508 = × 17 × 23 × 47, so it is divisible by 2.
What are the factors of 73508?
1, 2, 4, 17, 23, 34, 46, 47, 68, 92, 94, 188, 391, 782, 799, 1081, 1564, 1598, 2162, 3196, 4324, 18377, 36754, 73508.
What is 73508 in binary?
10001111100100100 (hexadecimal 11F24, octal 217444).
What is the square root of 73508?
About 271.1236, exactly 2√18377.
Is 73508 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 73508?
73508 is a Harshad number: divisible by its digit sum 23.