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The number 72433

72433 is a composite number with 4 divisors. Its prime factorisation is 113 × 641. Divisors (4): 1, 113, 641, 72433.

Number

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How to work it out

  1. 1

    What is special about 72433: a semiprime: 113 × 641, the product of two primes.

  2. 2

    72433 is composite. Its prime factorisation is

    72433=113×64172433 = 113 \times 641
  3. 3

    The divisors add up to 73188; without 72433 itself that is 755, so 72433 is deficient (755 is less than 72433). Euler's totient φ(72433) = 71680 numbers up to 72433 share no factor with it.

  4. 4

    The digits of 72433 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 42 steps to reach 1.

LaTeX source of the formulas on this page
\[ 72433 = 113 \times 641 \]

72433 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors73188
Euler totient φ(n)71680
Square5246539489
Cube380022594806737
Square root269.133796
Digit sum / digital root19 / 1
Collatz steps to 142
Scientific notation7.2433 × 10410^{4}

72433 in other forms

FormValue
In wordsseventy-two thousand four hundred and thirty-three
Binary (base 2)10001101011110001
Octal (base 8)215361
Hexadecimal (base 16)11AF1
Base 310200100201
As time72433 seconds = 20 h 7 min 13 s

Is 72433 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 72433 a prime number?

No. 72433 = 113 × 641, so it is divisible by 113.

What are the factors of 72433?

1, 113, 641, 72433.

What is 72433 in binary?

10001101011110001 (hexadecimal 11AF1, octal 215361).

What is the square root of 72433?

About 269.1338.

Is 72433 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 72433?

72433 is a semiprime: 113 × 641, the product of two primes.

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