The number 6999
6999 is a composite number with 4 divisors. Its prime factorisation is 3 × 2333. Divisors (4): 1, 3, 2333, 6999.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 6999: a semiprime: 3 × 2333, the product of two primes.
- 2
6999 is composite. Its prime factorisation is
- 3
The divisors add up to 9336; without 6999 itself that is 2337, so 6999 is deficient (2337 is less than 6999). Euler's totient φ(6999) = 4664 numbers up to 6999 share no factor with it.
- 4
The digits of 6999 add up to 33, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 132 steps to reach 1.
LaTeX source of the formulas on this page
\[ 6999 = 3 \times 2333 \]
6999 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 9336 |
| Euler totient φ(n) | 4664 |
| Square | 48986001 |
| Cube | 342853020999 |
| Square root | 83.660026 |
| Digit sum / digital root | 33 / 6 |
| Collatz steps to 1 | 132 |
| Scientific notation | 6.999 × |
6999 in other forms
| Form | Value |
|---|---|
| In words | six thousand nine hundred and ninety-nine |
| Binary (base 2) | 1101101010111 |
| Octal (base 8) | 15527 |
| Hexadecimal (base 16) | 1B57 |
| Base 3 | 100121020 |
| As time | 6999 seconds = 1 h 56 min 39 s |
Is 6999 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (6999 ÷ 3 = 2333) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 6999 a prime number?
No. 6999 = 3 × 2333, so it is divisible by 3.
What are the factors of 6999?
1, 3, 2333, 6999.
What is 6999 in binary?
1101101010111 (hexadecimal 1B57, octal 15527).
What is the square root of 6999?
About 83.6600.
Is 6999 divisible by 3?
Yes. Its digits add up to 33, a multiple of 3.
What is special about the number 6999?
6999 is a semiprime: 3 × 2333, the product of two primes.