The number 68921

No. 68921 = 41^3, so it is divisible by 41.

68921 is a perfect cube (41^3).

68921 is a perfect cube ( $41^{3}$ ). Its prime factorisation is $41^{3}$ . Divisors (4): 1, 41, 1681, 68921.

Number

Pick any whole number from 1 to 100,000.

68921 = 41^{3}

How to work it out

1
What is special about 68921: a perfect cube ( $41^{3}$ ).
2
68921 is composite. Its prime factorisation is
$68921 = 41^{3}$
3
The divisors add up to 70644; without 68921 itself that is 1723, so 68921 is deficient (1723 is less than 68921). Euler's totient φ(68921) = 67240 numbers up to 68921 share no factor with it.
4
The digits of 68921 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 174 steps to reach 1.

LaTeX source of the formulas on this page

\[ 68921 = 41^{3} \]

Form	Value
In words	sixty-eight thousand nine hundred and twenty-one
Binary (base 2)	10000110100111001
Octal (base 8)	206471
Hexadecimal (base 16)	10D39
Base 3	10111112122
As time	68921 seconds = 19 h 8 min 41 s

Divisor	Answer	Rule
2	No (remainder 1)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	No (remainder 2)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	No (remainder 1)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 1)	A number is divisible by 5 if the last digit is 0 or 5.
6	No (remainder 5)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 6)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	No (remainder 1)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 8)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 1)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 6)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	No (remainder 5)	A number is divisible by 12 if it is divisible by both 3 and 4.

Is 68921 a prime number?

No. 68921 = $41^{3}$ , so it is divisible by 41.

What are the factors of 68921?

1, 41, 1681, 68921.

What is 68921 in binary?

10000110100111001 (hexadecimal 10D39, octal 206471).

What is the square root of 68921?

About 262.5281, exactly 41√41.

Is 68921 divisible by 3?

No. Its digits add up to 26, which is not a multiple of 3.

What is special about the number 68921?

68921 is a perfect cube ( $41^{3}$ ).