The number 67473
67473 is a composite number with 30 divisors. Its prime factorisation is × × 17. Divisors (30): 1, 3, 7, 9, 17, 21, 27, 49, 51, 63, 81, 119, 147, 153, 189, 357 … 67473.
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How to work it out
- 1
What is special about 67473: a Harshad number: divisible by its digit sum 27.
- 2
67473 is composite. Its prime factorisation is
- 3
The divisors add up to 124146; without 67473 itself that is 56673, so 67473 is deficient (56673 is less than 67473). Euler's totient φ(67473) = 36288 numbers up to 67473 share no factor with it.
- 4
The digits of 67473 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 68 steps to reach 1.
LaTeX source of the formulas on this page
\[ 67473 = 3^{4} \times 7^{2} \times 17 \]67473 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 30 |
| Sum of divisors | 124146 |
| Euler totient φ(n) | 36288 |
| Square | 4552605729 |
| Cube | 307177966352817 |
| Square root | 259.755654 (= 63√17) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 68 |
| Scientific notation | 6.7473 × |
67473 in other forms
| Form | Value |
|---|---|
| In words | sixty-seven thousand four hundred and seventy-three |
| Binary (base 2) | 10000011110010001 |
| Octal (base 8) | 203621 |
| Hexadecimal (base 16) | 10791 |
| Base 3 | 10102120000 |
| As time | 67473 seconds = 18 h 44 min 33 s |
Is 67473 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (67473 ÷ 3 = 22491) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (67473 ÷ 7 = 9639) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (67473 ÷ 9 = 7497) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 67473 a prime number?
No. 67473 = × × 17, so it is divisible by 3.
What are the factors of 67473?
1, 3, 7, 9, 17, 21, 27, 49, 51, 63, 81, 119, 147, 153, 189, 357, 441, 459, 567, 833, 1071, 1323, 1377, 2499, 3213, 3969, 7497, 9639, 22491, 67473.
What is 67473 in binary?
10000011110010001 (hexadecimal 10791, octal 203621).
What is the square root of 67473?
About 259.7557, exactly 63√17.
Is 67473 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 67473?
67473 is a Harshad number: divisible by its digit sum 27.