The number 67397
67397 is a composite number with 6 divisors. Its prime factorisation is Ć 557. Divisors (6): 1, 11, 121, 557, 6127, 67397.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
67397 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
67397 is composite. Its prime factorisation is
- 3
The divisors add up to 74214; without 67397 itself that is 6817, so 67397 is deficient (6817 is less than 67397). Euler's totient Ļ(67397) = 61160 numbers up to 67397 share no factor with it.
- 4
The digits of 67397 add up to 32, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 130 steps to reach 1.
LaTeX source of the formulas on this page
\[ 67397 = 11^{2} \times 557 \]67397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 74214 |
| Euler totient Ļ(n) | 61160 |
| Square | 4542355609 |
| Cube | 306141140979773 |
| Square root | 259.609322 (= 11ā557) |
| Digit sum / digital root | 32 / 5 |
| Collatz steps to 1 | 130 |
| Scientific notation | 6.7397 Ć |
67397 in other forms
| Form | Value |
|---|---|
| In words | sixty-seven thousand three hundred and ninety-seven |
| Binary (base 2) | 10000011101000101 |
| Octal (base 8) | 203505 |
| Hexadecimal (base 16) | 10745 |
| Base 3 | 10102110012 |
| As time | 67397 seconds = 18 h 43 min 17 s |
Is 67397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (67397 Ć· 11 = 6127) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 67397 a prime number?
No. 67397 = Ć 557, so it is divisible by 11.
What are the factors of 67397?
1, 11, 121, 557, 6127, 67397.
What is 67397 in binary?
10000011101000101 (hexadecimal 10745, octal 203505).
What is the square root of 67397?
About 259.6093, exactly 11ā557.
Is 67397 divisible by 3?
No. Its digits add up to 32, which is not a multiple of 3.
What is special about the number 67397?
It is a composite number with 6 divisors.