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The number 67381

67381 is a composite number with 4 divisors. Its prime factorisation is 43 × 1567. Divisors (4): 1, 43, 1567, 67381.

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How to work it out

  1. 1

    What is special about 67381: a semiprime: 43 × 1567, the product of two primes.

  2. 2

    67381 is composite. Its prime factorisation is

    67381=43×156767381 = 43 \times 1567
  3. 3

    The divisors add up to 68992; without 67381 itself that is 1611, so 67381 is deficient (1611 is less than 67381). Euler's totient φ(67381) = 65772 numbers up to 67381 share no factor with it.

  4. 4

    The digits of 67381 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 130 steps to reach 1.

LaTeX source of the formulas on this page
\[ 67381 = 43 \times 1567 \]

67381 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors68992
Euler totient φ(n)65772
Square4540199161
Cube305923159667341
Square root259.578505
Digit sum / digital root25 / 7
Collatz steps to 1130
Scientific notation6.7381 × 10410^{4}

67381 in other forms

FormValue
In wordssixty-seven thousand three hundred and eighty-one
Binary (base 2)10000011100110101
Octal (base 8)203465
Hexadecimal (base 16)10735
Base 310102102121
As time67381 seconds = 18 h 43 min 1 s

Is 67381 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 67381 a prime number?

No. 67381 = 43 × 1567, so it is divisible by 43.

What are the factors of 67381?

1, 43, 1567, 67381.

What is 67381 in binary?

10000011100110101 (hexadecimal 10735, octal 203465).

What is the square root of 67381?

About 259.5785.

Is 67381 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 67381?

67381 is a semiprime: 43 × 1567, the product of two primes.

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    67381: is it prime? Factors, square root, binary, Roman numeral | WordGPT