The number 6489
6489 is a composite number with 12 divisors. Its prime factorisation is × 7 × 103. Divisors (12): 1, 3, 7, 9, 21, 63, 103, 309, 721, 927, 2163, 6489.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
6489 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
6489 is composite. Its prime factorisation is
- 3
The divisors add up to 10816; without 6489 itself that is 4327, so 6489 is deficient (4327 is less than 6489). Euler's totient φ(6489) = 3672 numbers up to 6489 share no factor with it.
- 4
The digits of 6489 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 49 steps to reach 1.
LaTeX source of the formulas on this page
\[ 6489 = 3^{2} \times 7 \times 103 \]6489 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 10816 |
| Euler totient φ(n) | 3672 |
| Square | 42107121 |
| Cube | 273233108169 |
| Square root | 80.554329 (= 3√721) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 49 |
| Scientific notation | 6.489 × |
6489 in other forms
| Form | Value |
|---|---|
| In words | six thousand four hundred and eighty-nine |
| Binary (base 2) | 1100101011001 |
| Octal (base 8) | 14531 |
| Hexadecimal (base 16) | 1959 |
| Base 3 | 22220100 |
| As time | 6489 seconds = 1 h 48 min 9 s |
Is 6489 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (6489 ÷ 3 = 2163) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (6489 ÷ 7 = 927) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (6489 ÷ 9 = 721) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 6489 a prime number?
No. 6489 = × 7 × 103, so it is divisible by 3.
What are the factors of 6489?
1, 3, 7, 9, 21, 63, 103, 309, 721, 927, 2163, 6489.
What is 6489 in binary?
1100101011001 (hexadecimal 1959, octal 14531).
What is the square root of 6489?
About 80.5543, exactly 3√721.
Is 6489 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 6489?
It is a composite number with 12 divisors.