The number 63121
63121 is a composite number with 8 divisors. Its prime factorisation is 17 × 47 × 79. Divisors (8): 1, 17, 47, 79, 799, 1343, 3713, 63121.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
63121 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
63121 is composite. Its prime factorisation is
- 3
The divisors add up to 69120; without 63121 itself that is 5999, so 63121 is deficient (5999 is less than 63121). Euler's totient φ(63121) = 57408 numbers up to 63121 share no factor with it.
- 4
The digits of 63121 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 179 steps to reach 1.
LaTeX source of the formulas on this page
\[ 63121 = 17 \times 47 \times 79 \]
63121 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 69120 |
| Euler totient φ(n) | 57408 |
| Square | 3984260641 |
| Cube | 251490515920561 |
| Square root | 251.238930 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 179 |
| Scientific notation | 6.3121 × |
63121 in other forms
| Form | Value |
|---|---|
| In words | sixty-three thousand one hundred and twenty-one |
| Binary (base 2) | 1111011010010001 |
| Octal (base 8) | 173221 |
| Hexadecimal (base 16) | F691 |
| Base 3 | 10012120211 |
| As time | 63121 seconds = 17 h 32 min 1 s |
Is 63121 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 63121 a prime number?
No. 63121 = 17 × 47 × 79, so it is divisible by 17.
What are the factors of 63121?
1, 17, 47, 79, 799, 1343, 3713, 63121.
What is 63121 in binary?
1111011010010001 (hexadecimal F691, octal 173221).
What is the square root of 63121?
About 251.2389.
Is 63121 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 63121?
It is a composite number with 8 divisors.