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The number 61477

61477 is a composite number with 4 divisors. Its prime factorisation is 13 × 4729. Divisors (4): 1, 13, 4729, 61477.

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How to work it out

  1. 1

    What is special about 61477: a semiprime: 13 × 4729, the product of two primes.

  2. 2

    61477 is composite. Its prime factorisation is

    61477=13×472961477 = 13 \times 4729
  3. 3

    The divisors add up to 66220; without 61477 itself that is 4743, so 61477 is deficient (4743 is less than 61477). Euler's totient φ(61477) = 56736 numbers up to 61477 share no factor with it.

  4. 4

    The digits of 61477 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 104 steps to reach 1.

LaTeX source of the formulas on this page
\[ 61477 = 13 \times 4729 \]

61477 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors66220
Euler totient φ(n)56736
Square3779421529
Cube232347497338333
Square root247.945559
Digit sum / digital root25 / 7
Collatz steps to 1104
Scientific notation6.1477 × 10410^{4}

61477 in other forms

FormValue
In wordssixty-one thousand four hundred and seventy-seven
Binary (base 2)1111000000100101
Octal (base 8)170045
Hexadecimal (base 16)F025
Base 310010022221
As time61477 seconds = 17 h 4 min 37 s

Is 61477 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 61477 a prime number?

No. 61477 = 13 × 4729, so it is divisible by 13.

What are the factors of 61477?

1, 13, 4729, 61477.

What is 61477 in binary?

1111000000100101 (hexadecimal F025, octal 170045).

What is the square root of 61477?

About 247.9456.

Is 61477 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 61477?

61477 is a semiprime: 13 × 4729, the product of two primes.

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