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The number 61433

61433 is a composite number with 4 divisors. Its prime factorisation is 23 × 2671. Divisors (4): 1, 23, 2671, 61433.

Number

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How to work it out

  1. 1

    What is special about 61433: a semiprime: 23 × 2671, the product of two primes.

  2. 2

    61433 is composite. Its prime factorisation is

    61433=23×267161433 = 23 \times 2671
  3. 3

    The divisors add up to 64128; without 61433 itself that is 2695, so 61433 is deficient (2695 is less than 61433). Euler's totient φ(61433) = 58740 numbers up to 61433 share no factor with it.

  4. 4

    The digits of 61433 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 179 steps to reach 1.

LaTeX source of the formulas on this page
\[ 61433 = 23 \times 2671 \]

61433 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors64128
Euler totient φ(n)58740
Square3774013489
Cube231848970669737
Square root247.856814
Digit sum / digital root17 / 8
Collatz steps to 1179
Scientific notation6.1433 × 10410^{4}

61433 in other forms

FormValue
In wordssixty-one thousand four hundred and thirty-three
Binary (base 2)1110111111111001
Octal (base 8)167771
Hexadecimal (base 16)EFF9
Base 310010021022
As time61433 seconds = 17 h 3 min 53 s

Is 61433 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 61433 a prime number?

No. 61433 = 23 × 2671, so it is divisible by 23.

What are the factors of 61433?

1, 23, 2671, 61433.

What is 61433 in binary?

1110111111111001 (hexadecimal EFF9, octal 167771).

What is the square root of 61433?

About 247.8568.

Is 61433 divisible by 3?

No. Its digits add up to 17, which is not a multiple of 3.

What is special about the number 61433?

61433 is a semiprime: 23 × 2671, the product of two primes.

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